(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2) 2x²+3x-18=0 3x²+2x-5=0 x²-4x-7=0.解一元二

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/19 15:06:15
(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2) 2x²+3x-18=0 3x²+2x-5=0 x²-4x-7=0.解一元二

(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2) 2x²+3x-18=0 3x²+2x-5=0 x²-4x-7=0.解一元二
(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=
(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0
2(x-1=(x-1)(x-2) 2x²+3x-18=0 3x²+2x-5=0 x²-4x-7=0.解一元二次 麻烦拉

(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2)=0 (2x-1)²=9 x²-7x+6=0 x(x-1)=x 2x²-5x-12=0 2(x-1=(x-1)(x-2) 2x²+3x-18=0 3x²+2x-5=0 x²-4x-7=0.解一元二
1) x=1或2
2)化简得2x-1=±3 x=2或-1
3)因式分解(x-1)(x-6)=0 x=1或6
4)原式即x(x-2)=0 x=0或2
5)因式分解(x-4)(2x+3)=0 x=4或-3/2
6)化简后因式分解得(x-1)(x-4)=0 x=1或4
7)求根公式得x=(-3±根号153)/4
8)因式分解得(x-1)(3x+5)=0 x=1或-5/3
9)求根公式得x=2±根号11

(x)-2x·x-x-2x+1=0求x的值, 请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360 先化简再求值(x-1/x-x-2/x+1)/(2x²-x/x²+2x+1)且x²-x-1 =0 (X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0 f(x)=(x+1)ln(x+1)+m(x^2+2x) x>=0时,f(x) 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X (1-3/x+2)÷x-1/x²+2x-x/x+1,其中x满足x²-x-1=0 已知X²-3x-2=0,求 2x-1 x-1 ----- ÷ -------- 的值 (x- x) x²-2x不能先求X f(x)=x/(1+x) x>=0 f1(X)=f(X) fn(X)=fn-1[fn-1(x)]求fn(x)证明:f1(X)+2f2(X)+3f3(x)+……+nfn(X) 已知f(x)= -x^2-2x g(x)= 分段函数 x+1/4x(x>0),x+1(x 判断函数奇偶性,快,f(x)=a(x属于R)f(x)=x^2 (1-x) ,x大于等于0x^2 (1+x) ,x (2x-2)(x-1)=0 x(x-5)=5x-10 画出f(x)={(x+1 x≥0) (x-2 x 解方程:x(x-1)+x(2+x)=2x(x-2) 已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方,x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√(1/4)-√(1/2) 若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂) f(x)=(x^3-2)/[2(x-1)^2]求导f'(x)=[6x²(x-1)²-4(x³-2)(x-1)]/[2(x-1)²]²>0即 6x²(x-1)²-4(x³-2)(x-1)>0 (x-1)[6x²(x-1)-4(x³-2)]>0 (x-1)[6x³-6x²-4x³+8]>0 (x-1)(x³-3x²+4)>0 (x- 1、1/2x=2/x+32、x/x+1=(2x/3x+3)+13、2/x-1=4/x²-14、5/x²+x-1/x²-x=0