(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)还有一道：(1-4x)^2/2x+3(4x^2+12x+9)/(4x-1)(1-4x)^2/（2x+3）(4x^2+12x+9)/(4x-1)第二题应该是这样的、不好意思、要有过程！

来源：学生作业帮助网编辑：作业帮时间：2024/04/24 18:17:15

(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)还有一道：(1-4x)^2/2x+3*(4x^2+12x+9)/(4x-1)(1-4x)^2/（2x+3）*(4x^2+12x+9)/(4x-1)第二题应该是这样的、不好意思、要有过程！
(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)
还有一道：(1-4x)^2/2x+3*(4x^2+12x+9)/(4x-1)
(1-4x)^2/（2x+3）*(4x^2+12x+9)/(4x-1)
第二题应该是这样的、不好意思、要有过程！

(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)还有一道：(1-4x)^2/2x+3*(4x^2+12x+9)/(4x-1)(1-4x)^2/（2x+3）*(4x^2+12x+9)/(4x-1)第二题应该是这样的、不好意思、要有过程！
(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)
= (x-1)/{(x-2)(x-3)} + (x-2)/{x-1)(x-3)} + (x-3)/{(x-1)(x-2)}
= { (x-1)^2 + (x-2)^2 + (x-3)^2 } / { (x-1)(x-2)(x-3) }
= (x^2-2x+1+x^2-4x+4+x^2-6x+9) / { (x-1)(x-2)(x-3) }
= (3x^2-12x+14) / (x-1)(x-2)(x-3)
(1-4x)^2/(2x+3) * (4x^2+12x+9)/(4x^2-1)
= (4x-1)^2/(2x+3) * (2x+3)^2/(4x-1)
= (4x-1) * (2x+3)
= 8x^2+10x-3

一、(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2) =(x-1)/【（x-2)(x-3)】+(x-2)/【(x-1)(x-3)】+(x-3)/【(x-1)(x-2)】=[(x-1)^2+(x-2)^2+(x-3)^2/【(x-1)（x-2)(x-3)】=[(x-1)^2+(x-2)^2+(x-3)^2/【(x-1)（x-2)(x-3)】=(3x...

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