已知a已知a
已知a√(a^2-2a+1)/(a^2-a)=|a-1|/[a(a-1)]=(1-a)/[a(a-1)]=-1/a
没看明白题意
a<1a-1<0|a-1|=-(a-1)原式=√(a-1)²/[a(a-1)]=|a-1|[a(a-1)]=-(a-1)/[a(a-1)]=-1/a