x+y=0.5 x+3y=1.2 求3x2 +12xy +9y2

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x+y=0.5 x+3y=1.2 求3x2 +12xy +9y2

x+y=0.5 x+3y=1.2 求3x2 +12xy +9y2
x+y=0.5 x+3y=1.2 求3x2 +12xy +9y2

x+y=0.5 x+3y=1.2 求3x2 +12xy +9y2
∵x+y=0.5 x+3y=1.2
∴3x2 +12xy +9y2
=3(x²+4xy+3y²)
=3(x+y)(x+3y)
=3×½×1.2
=1.8

3x2 +12xy +9y2
=3(x+y)(x+3y)
=3*0.5*1.2
=1.8

3x2 +12xy +9y2
=3(x^2+4xy+3y^2)
=3(x+y)(x+3y)
=3*0.5*1.2
=1.8

3×2什么意思

1.8

问题是如果是三爱克斯的平方加12xy加九外的平方那么答案是1.8
需要过程吗?