作业帮已知函数f（x）=1/(x+1)+log以3为底的2-x/x的对数,当x为何值时,f[x(x-1/2)]>1/2
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 10:39:12
![已知函数f（x）=1/(x+1)+log以3为底的2-x/x的对数,当x为何值时,f[x(x-1/2)]>1/2](/uploads/image/z/332437-13-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3D1%2F%28x%2B1%29%2Blog%E4%BB%A53%E4%B8%BA%E5%BA%95%E7%9A%842-x%2Fx%E7%9A%84%E5%AF%B9%E6%95%B0%2C%E5%BD%93x%E4%B8%BA%E4%BD%95%E5%80%BC%E6%97%B6%2Cf%5Bx%28x-1%2F2%29%5D%3E1%2F2)
已知函数f（x）=1/(x+1)+log以3为底的2-x/x的对数,当x为何值时,f[x(x-1/2)]>1/2
已知函数f（x）=1/(x+1)+log以3为底的2-x/x的对数,当x为何值时,f[x(x-1/2)]>1/2
已知函数f（x）=1/(x+1)+log以3为底的2-x/x的对数,当x为何值时,f[x(x-1/2)]>1/2
因为x+1≠0,2-x/x>0,
所以f(x)的定义域为0