2^a=5^b=m,且1/a+1/b=2,则m等于

2^a=5^b=m,且1/a+1/b=2,则m等于
2^a=5^b=m,且1/a+1/b=2,则m等于

2^a=5^b=m,且1/a+1/b=2,则m等于
2^a=5^b=m,
取对数
则：alg2=blg5=lgm,
得：1/a=lg2/lgm,1/b=lg5/lgm .
1/a+1/b
=lg2/lgm+lg5/lgm
=(lg2+lg5)/lgm
=lg(2×5)/lgm
=1/lgm
=2
得：lgm=1/2
则：m=√10 .