2lg(5/3)-lg(7/4)+2lg3+(1/2)lg49(lg2)^2+lg2lg5+lg50lg(5^2)+2/3lg8+lg5lg20+(lg2)^2

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2lg(5/3)-lg(7/4)+2lg3+(1/2)lg49(lg2)^2+lg2lg5+lg50lg(5^2)+2/3lg8+lg5lg20+(lg2)^2

2lg(5/3)-lg(7/4)+2lg3+(1/2)lg49(lg2)^2+lg2lg5+lg50lg(5^2)+2/3lg8+lg5lg20+(lg2)^2
2lg(5/3)-lg(7/4)+2lg3+(1/2)lg49
(lg2)^2+lg2lg5+lg50
lg(5^2)+2/3lg8+lg5lg20+(lg2)^2

2lg(5/3)-lg(7/4)+2lg3+(1/2)lg49(lg2)^2+lg2lg5+lg50lg(5^2)+2/3lg8+lg5lg20+(lg2)^2
2lg(5/3)-lg(7/4)+2lg3+(1/2)lg49
=lg(25/9)+lg9-(lg(7/4)-lg7)
=lg25-lg(1/4)
=lg(25*4)
=lg100
=2.
(lg2)^2+lg2lg5+lg50
=(lg2)^2+lg2lg5+lg5+lg10
=(lg2)^2+lg2lg5+lg5+1.
=lg2*(lg2+lg5)+lg5+1
=lg2+lg5+1
=lg(2*5)+1
=2.
lg(5^2)+2/3lg8+lg5lg20+(lg2)^2
=2lg5+2lg2+lg5lg20+(lg2)^2
=2(lg5+lg2)+lg5*(lg5+lg4)+(lg2)^2
=2+(lg5)^2+2lg2lg5+(lg2)^2
=2+(lg5)^2+lg2*(lg25+lg2)
=2+(lg5)^2+lg2*lg5+lg2
=2+lg5*(lg2+lg5)+lg2
=2+lg5+lg2
=2+lg(5*2)
=3.

第一题是2
第2题也是2 第3题=3

用对数基本公式
1.10
2.题目错了中间 项由个2 答案为1
3.3 20=4*5 将题目化未lg2 和lg5
(因为我键盘问题过程省略了)