(xy+1)^2+(x+y)(x+y-2xy-2)怎么解啊是因式分解

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(xy+1)^2+(x+y)(x+y-2xy-2)怎么解啊是因式分解

(xy+1)^2+(x+y)(x+y-2xy-2)怎么解啊是因式分解
(xy+1)^2+(x+y)(x+y-2xy-2)怎么解啊是因式分解

(xy+1)^2+(x+y)(x+y-2xy-2)怎么解啊是因式分解
令a=xy,b=x+y
原式=(a+1)²+b(b-2a-2)
=a²+2a+1+b²-2ab-2b
=(a²-2ab+b²)+2a-2b+1
=(a-b)²+2(a-b)+1
=(a-b+1)²
=(xy-x-y+1)²
=[x(y-1)-(y-1)]²
=(y-1)²(x-1)²

（xy+1）²-2（xy+1)(x+y)+(x+y)²
=(xy+1-x-y)²
=【（xy-y)-(x-1)]²
=【y(x-1)-(x-1)]²
=（x-1)²（y-1)²

如图

爪机党

有点慢

.(x+y-2)(x+y-2xy)+(xy-1)^2 (x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1) 1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y) {(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1) (-x-y)(x^2+xy+y^2) 化简x^-y^/x^-2xy+y^ 2*(x-y)²(y-x)(xy) （x^2+xy/x-y)/（xy/x-y)计算 (x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简 因式分解x^2y^2+x^2y+xy^2+3xy+x+y+1 若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思，是3x-2xy-3y/x-2xy-y X-Y/2X+2Y XY/X+Y² 因式分解：x×x-xy-2y×y-x-y 计算3xy[2xy-x(y-2)+x-1] xy-x-y+1/y²-2y+1 y平方-2y+1分之xy-x-y-1 x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x² [(x+y)^2-(x-y)^2]÷(1/2xy)