x+y+z=6 x+2y+3z=14 y+1=z
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x+y+z=6 x+2y+3z=14 y+1=z
x+y+z=6 x+2y+3z=14 y+1=z
x+y+z=6 x+2y+3z=14 y+1=z
x+y+y+1=6;
x+2y+3(y+1)=14.
x+2y=5;
x+5y=11.
5-2y+5y=11:
3y=6;y=2.
x=5-2y=1;z=y+1=3.
x+y+y+1=6=x+2y+1=6 14-6=8 3z=8 z=8/3 y=3/8-1=3/5
汗,把z=y+1代入x+y+z=6中,写出x等于多少,x的那个式子中有z,再把z代入进去,把第二个式子化成只有z的式子,解出z,继而x、y
x=1 y=2 z=3
你个死蠢
x+y+z=6
x+2y+3z=14
y+1=z
可将第三个式子带入前两个,得到:
x+y+(y+1)=6
x+2y+3(y+1)=14
分别化简之后相减,可算出 x= 1 y=2 然后可得z= 3
x=1 y=2 z=3
x=1 y=2 z=3
x+y+z=6 x+2y+3z=14 y+1=z
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