若a/b=c/d=f/e=3/5,且,b-2d+3e不等于0则(a-2c+3f)/(b-2d+3e)是多少?

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若a/b=c/d=f/e=3/5,且,b-2d+3e不等于0则(a-2c+3f)/(b-2d+3e)是多少?

若a/b=c/d=f/e=3/5,且,b-2d+3e不等于0则(a-2c+3f)/(b-2d+3e)是多少?
若a/b=c/d=f/e=3/5,且,b-2d+3e不等于0则(a-2c+3f)/(b-2d+3e)是多少?

若a/b=c/d=f/e=3/5,且,b-2d+3e不等于0则(a-2c+3f)/(b-2d+3e)是多少?
∵a/b=c/d=f/e=3/5∴a=3/5×b,c=3/5×d,f=3/5×e~∴〈a-2c+3f〉=〈3/5×b-2×3/5×d+3×3/5×e〉=3/5×〈b-2d+3e〉~∴原式=3/5