(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
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(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
原式=[log(2的平方)3+log(2的三方)3][log(3)2+log(3的平方)2的三方] =[0.5log(2)3+三分之一log(2)3][log(3)2+二分之三(3)2] =[六分之五log(2)3 ][二分之五log(3)2] =十二分之二十五(lg3除以lg2)(lg2除以lg3) =十二分之二十五 先化成同底对数,再运用恒等式,再运用换底公式,得出结果.手动,欢迎追加分.
4^[log(2)3+log(4)8]
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
化简:(log^3 2+log^9 2)(log^4 3+log^8 3)
(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路
log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃....
求值:(log(4)3+log(8)3)×(log(3)2+log(9)2)+log(2)(2^5)¼
log(75)10-log(3)10+log(4)10
log(8)(3)×log²(3)(4)=
(log(4)3+log(8)3)*lg2/lg3
对数:log(4)8-log(1/9)3 求值
log(2)9log(3)4等于
log(27)16/log(3)4=
log(2)9×log(3)4
有关对数的计算题(log(4)3+log(8)3)(log(3)2+log(9)2)=?
化简(log[4]3+log[8]3)×(log[3]2+log[9]2)如题
(log(3)2+log(9)2)*(log(4)3+log(8)3) 带括号的是底数
(LOG(3,4)+LOG(3,8))(LOG(2,3)+LOG(2,9))等于几 看的懂吧
(iog(4)3+log(8)3)(log(3)2+log(9)8)怎样计算