作业帮这段代码如何减少运算时间#include<stdio.h>int main(){ int t; scanf("%d\n",&t); int a[t][3],i; for(i=0;i<=t-1;i++) { scanf("%d %d %d",&a[i][0],&a[i][1],&a[i][2]); } in
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/10 09:58:05
![这段代码如何减少运算时间#include<stdio.h>int main(){ int t; scanf("%d\n",&t); int a[t][3],i; for(i=0;i<=t-1;i++) { scanf("%d %d %d",&a[i][0],&a[i][1],&a[i][2]); } in](/uploads/image/z/8727466-58-6.jpg?t=%E8%BF%99%E6%AE%B5%E4%BB%A3%E7%A0%81%E5%A6%82%E4%BD%95%E5%87%8F%E5%B0%91%E8%BF%90%E7%AE%97%E6%97%B6%E9%97%B4%23include%26lt%3Bstdio.h%26gt%3Bint+main%28%29%7B++++int+t%3B++++scanf%28%26quot%3B%25d%5Cn%26quot%3B%2C%26amp%3Bt%29%3B++++int+a%5Bt%5D%5B3%5D%2Ci%3B++++for%28i%3D0%3Bi%26lt%3B%3Dt-1%3Bi%2B%2B%29++++%7B++++++++scanf%28%26quot%3B%25d+%25d+%25d%26quot%3B%2C%26amp%3Ba%5Bi%5D%5B0%5D%2C%26amp%3Ba%5Bi%5D%5B1%5D%2C%26amp%3Ba%5Bi%5D%5B2%5D%29%3B++++%7D++++in)
这段代码如何减少运算时间#include<stdio.h>int main(){ int t; scanf("%d\n",&t); int a[t][3],i; for(i=0;i<=t-1;i++) { scanf("%d %d %d",&a[i][0],&a[i][1],&a[i][2]); } in
这段代码如何减少运算时间
#include<stdio.h>
int main()
{
int t;
scanf("%d\n",&t);
int a[t][3],i;
for(i=0;i<=t-1;i++)
{
scanf("%d %d %d",&a[i][0],&a[i][1],&a[i][2]);
}
int f,d,sum;
for(i=0;i<=t-1;i++)
{
sum=0;
for(d=a[i][0];d<=a[i][1];d=d+2)
sum=sum+d*d;
f=sum%a[i][2];
printf("%d\n",f);
}
}
这段代码如何减少运算时间#include<stdio.h>int main(){ int t; scanf("%d\n",&t); int a[t][3],i; for(i=0;i<=t-1;i++) { scanf("%d %d %d",&a[i][0],&a[i][1],&a[i][2]); } in
#include <stdio.h>
int getResult(int a, int b, int m)
{
int n = (b - a) / 2 + 1;
int sum = n*a*b + 2*n*(n-1)*(2*n-1) / 3;
return sum % m;
}
int main()
{
int i;
scanf("%d", &i);
while(i --> 0) {
int a, b, m;
scanf("%d%d%d", &a, &b, &m);
printf("%d\n", getResult(a, b, m));
}
return 0;
}
算sum的过程直接套公式就好了……?